If tan θ + cot θ = 5, find the value of tan2 θ + cot2 θ.
Answer:
23
- tan θ + cot θ = 5
- On squaring both sides,
(tan θ + cot θ)2 = 52 - tan2θ + cot2θ + 2 tanθ cotθ = 25
- tan2θ + cot2θ + 2 = 25
- tan2θ + cot2θ = 25 - 2 = 23