Find an equation of the circle with center at origin and radius | Math Question and Answer | Edugain Vietnam

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Find an equation of the circle with center at origin and radius $4$ .

Answer:

$x^2 + y^2 = 16$

Step by Step Explanation:

The equation of a circle with center at $(a, b)$ and radius $r$ is given by
$(x - a)^2 + (y - b)^2 = r^2$
Given:
Center of the circle is at center $i.e(0,0)$
Radius of the circle $= 4$
$\implies a = 0, b = 0,$ and $r = 4$
Therefore, the equation of the circle is given by
$(x - 0)^2 + (y - 0)^2 = 4^2 \\ \implies x^2 + y^2 = 16$
Hence, the required equation is $x^2 + y^2 = 16$ .

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