A die is thrown once. What is the probability of getting a number lying between 111 and 555 ?
Answer:
121212
- We know that in a single throw of a die we can get 1,2,3,4,5,1,2,3,4,5,1,2,3,4,5, or 6.6.6.
So, the total number of possible outcomes =666. - Let EEE be an event of getting a number lying between 111 and 555.
The event EEE will happen when the number on the die is 2,3,2,3,2,3, or 444.
Thus, the number of favorable outcomes = 333. - We know that the probability of occurrence of an event EEE, denoted by P(E)P(E)P(E) is defined as P(E)= Number of favorable outcomes Total number of possible outcomes P(E)= Number of favorable outcomes Total number of possible outcomes P(E)= Number of favorable outcomes Total number of possible outcomes
- Therefore, P( getting a number lying betweeen 1 and 5)=P(E)=36=12P( getting a number lying betweeen 1 and 5)=P(E)=36=12P( getting a number lying betweeen 1 and 5)=P(E)=36=12